Free, step-by-step NCERT Solutions for the Binomial Theorem — expanding any power of a binomial without multiplying it out term by term, using Pascal's Triangle and the general-term formula — plus the Miscellaneous Exercise of divisibility proofs, expansion shortcuts, approximations, and trinomial expansions. Solved the way CBSE awards marks, with the key formulas and the mistakes that cost students marks every year, right on this page.
The Binomial Theorem answers a simple question in a powerful way: instead of multiplying (a + b) by itself n times to expand (a + b)ⁿ, is there a direct formula for every term? Pascal's Triangle already hints at the answer for small powers, and the Binomial Theorem generalises it into a single formula that works for any positive integer n. Once that formula is in hand, the chapter turns to its uses — finding one specific term without expanding the whole thing, proving divisibility results, approximating expressions like (1.02)⁶, and expanding expressions with three terms instead of two.
This Class 11 Maths NCERT Solutions Chapter 7 hub covers the Binomial Theorem, the chapter that gives a direct formula for expanding (a + b)ⁿ for any positive integer n, instead of multiplying it out step by step. The chapter opens with Pascal's Triangle, where each row's entries are exactly the coefficients that appear when (a + b)ⁿ is expanded, and shows how these coefficients — the binomial coefficients nCr — are built from the same combinatorial idea used in counting. The Binomial Theorem then states this pattern as a single formula: (a + b)ⁿ = Σ nCr aⁿ⁻ʳ bʳ, summed over r from 0 to n.
Exercise 7.1 puts this formula to work — expanding binomials for a given power, computing specific powers like (101)⁴ or (99)⁵ by writing them as a binomial in disguise, and using the expansion to prove divisibility results. The Miscellaneous Exercise pushes further into the theorem's more demanding applications: finding a required term without expanding the whole binomial, comparing coefficients between two different expansions, using the first couple of terms of an expansion to approximate a number like (0.99)⁵, and expanding trinomials such as (2x + 3y + 4z)ⁿ by treating two of the three terms as a single binomial term first.
Where the coefficients of a binomial expansion come from, row by row. Exercise 7.1.
(a + b)ⁿ = Σ nCr aⁿ⁻ʳ bʳ — one formula for every power. Exercise 7.1.
Writing numbers like 101 as (100 + 1) to compute powers, and proving divisibility results. Exercise 7.1.
The general term, approximations, and trinomial expansions. Misc. Exercise.
Everything you need before you start solving. This is a summary for quick recall — the Formula Cards below has the full printable version for all of the Binomial Theorem.
Expands any power of a binomial directly, without repeated multiplication.
The same coefficients that appear as entries in Pascal's Triangle, one row per value of n.
Same formula as (a + b)ⁿ, but the sign alternates term by term — a very common place to slip up.
Splitting a number close to a round value into a sum makes the expansion mostly one large term plus a few small corrections.
Expanding (1 + x)ⁿ and grouping every term except the first shows the whole expression is a multiple of x.
Follows immediately by substituting a = b = 1 into the Binomial Theorem.
Gives any single term of the expansion directly — note the term index is r + 1, not r.
Keeping only the first two terms of an expansion gives a fast, accurate estimate when x is small.
Group two of the three terms into one, expand with the Binomial Theorem, then expand each (a + b) power again.
A quick way to decide, once you know what the question is actually asking for.
| What the question is asking | Use this | Why |
|---|---|---|
| Expand (a + b)ⁿ or (a − b)ⁿ for a given n | Binomial Theorem formula | Write out each term nCr aⁿ⁻ʳbʳ, alternating signs if the binomial has a minus (§7.2). |
| Compute a power like (101)⁴ or (99)⁵ | Rewrite as a binomial first | Split the number into a round value plus a small correction, e.g. 101 = 100 + 1, then expand (§7.2). |
| Prove an expression is divisible by some number | Expand and group terms | Write the expression as (1 + x)ⁿ or similar, expand, and show every term after the first shares the required factor (§7.2). |
| Find one specific term of an expansion, without expanding fully | General term formula | Use T(r+1) = nCr aⁿ⁻ʳbʳ and solve for the value of r that gives the required term (Misc. Exercise). |
| Estimate a value like (0.99)⁵ or (1.02)⁶ | Keep only the first two or three terms | Write the number as (1 + x)ⁿ with x small, and drop the higher-power terms as negligible (Misc. Exercise). |
| Expand something with three terms, like (2x + 3y + 4z)ⁿ | Group two terms, expand twice | Treat (2x + 3y) as one binomial term first, expand with the theorem, then expand each resulting power again (Misc. Exercise). |
Drawn from where students actually lose marks across both exercises.
Binomial Theorem for Positive Integral Indices — expansions, computing powers, and divisibility proofs · 14 questions
Solve Exercise 7.1 →Divisibility proofs, expansion shortcuts, approximations, and trinomial expansions · 6 questions
Solve Miscellaneous →Every formula for the Binomial Theorem — plus every other Class 11 Maths chapter — in one printable PDF.
Get Formula Cards →Quick answers from Class 11 Maths NCERT Solutions Chapter 7, Binomial Theorem.
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