Class 10 Science NCERT Solutions Chapter 10: The Human Eye and the Colourful World | Boundless Maths
👁️ Science · CBSE 2026-27 Unit III · Natural Phenomena ✨ Free — No Sign-up 19 Questions

Chapter 10: The Human Eye
and the Colourful World

Class 10 Science NCERT Solutions Chapter 10 (CBSE 2026-27) — every in-text question, every embedded Activity question, and all 12 back-of-chapter Exercises on this one page, solved with full working.

The Human Eye and the Colourful World applies everything learnt about lenses in Chapter 9 to the eye itself — the cornea, iris, pupil, retina, and the eye lens's remarkable power of accommodation — before covering the three common refractive defects of vision (myopia, hypermetropia, presbyopia) and exactly how concave and convex corrective lenses fix each one. It then turns to the optics of everyday natural phenomena: how a prism disperses white light into its seven colours, how a rainbow forms, why stars twinkle but planets don't, why sunrise and sunset appear a little early and late, and why the sky is blue. These NCERT solutions work through every Activity-based conceptual question and the full 12-question Exercise set with complete step-by-step working for every lens-power calculation.

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In-text & Exercise Coverage
Overview

What Chapter 10 Is Really About

The Human Eye and the Colourful World is really two chapters in one, connected by the same optics from Chapter 9. The first half treats the eye as a living camera — a cornea that does most of the refracting, an eye lens whose curvature the ciliary muscles adjust (accommodation) to keep images sharply focused on the retina, and the three refractive defects — myopia, hypermetropia, presbyopia — that show up when this system can't quite do its job, each corrected with the right concave or convex lens. The second half turns outward, to what light does once it leaves a prism or the atmosphere: why a prism splits white light into a band of seven colours (dispersion), how that same idea explains a rainbow, why the atmosphere bends starlight enough to make stars twinkle but not planets, why the sun appears to rise a little early and set a little late, and why scattering by air molecules paints the sky blue. Every question woven through the chapter is solved here, in the order the textbook presents it: the one "QUESTIONS" box after the defects-of-vision section, the questions embedded directly inside the prism and dispersion Activities, and the full 12-question Exercise set at the end, with complete numerical working for every lens-power calculation.

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The Eye & Accommodation

Cornea, iris, pupil and retina; how the ciliary muscles adjust the eye lens's focal length to focus near and far objects.

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Myopia & Hypermetropia

Why distant or nearby objects blur, and exactly which lens — and what power — corrects each defect.

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Dispersion, Scattering & the Sky

Prisms, rainbows, twinkling stars, early sunrise and late sunset, and why a clear sky looks blue.

Section A

In-text Questions — Defects of Vision (Page 164)

4 Questions
10.2 · Q1What is meant by power of accommodation of the eye?▾

The power of accommodation is the ability of the eye to adjust the focal length of its lens, using the ciliary muscles, so that it can focus clearly on objects placed at different distances — both near and far.

10.2 · Q2A person with a myopic eye cannot see objects beyond 1.2 m distinctly. What type of corrective lens should be used?▾

A concave lens of suitable power should be used. It diverges the incoming light rays so that the image of a distant object forms exactly on the retina instead of in front of it, correcting the myopia (near-sightedness).

10.2 · Q3What is the far point and near point of the human eye with normal vision?▾

Near point: about 25 cm from the eye. Far point: infinity. A normal eye can see objects clearly anywhere between these two points.

10.2 · Q4A student has difficulty reading the blackboard while sitting in the last row. What defect might this be, and how is it corrected?▾

The student is likely suffering from myopia (near-sightedness) — they can see nearby objects clearly but not distant ones, like the blackboard from the back of the class. This can be corrected by using spectacles with a concave lens of suitable power.

Section B

Embedded Activity Questions

3 Questions
Activity 10.1Compare the angle of incidence and angle of refraction at each surface of the prism. Is this similar to the bending that occurs in a glass slab?▾

At the first surface (air to glass), the ray bends towards the normal — the angle of refraction is smaller than the angle of incidence. At the second surface (glass to air), the ray bends away from the normal — the angle of emergence is larger than the angle of refraction at that surface.

This is not the same as a glass slab. In a slab, the two refracting surfaces are parallel, so the emergent ray comes out parallel to the incident ray (only laterally displaced). In a prism, the two refracting surfaces are inclined to each other, so the emergent ray is not parallel to the incident ray — it bends at an angle, called the angle of deviation.

Activity 10.2What do you observe when white light passes through a prism onto a screen? Why does this happen?▾

A beautiful band of colours — Violet, Indigo, Blue, Green, Yellow, Orange, Red (VIBGYOR) — appears on the screen. This happens because white light is actually made up of these seven colours, and each colour bends through a different angle as it passes through the prism (violet bends the most, red the least), due to their differing refractive indices. This causes the colours to separate and emerge along different paths — a phenomenon called dispersion.

Page 169'Danger' signal lights are red in colour. Why?▾

Red light is scattered the least by fog, smoke, or other particles in the atmosphere (since it has the longest wavelength among visible colours). This means red light can travel the farthest distance while remaining visible in its original colour, making it ideal for danger/warning signals that need to be seen clearly from far away.

Section C

End-of-Chapter Exercises (Q1–Q12)

12 Questions
Q1The human eye can focus on objects at different distances by adjusting the focal length of the eye lens. This is due to (a) presbyopia (b) accommodation (c) near-sightedness (d) far-sightedness▾

Answer: (b) accommodation

Q2The human eye forms the image of an object at its (a) cornea (b) iris (c) pupil (d) retina▾

Answer: (d) retina

Q3The least distance of distinct vision for a young adult with normal vision is about (a) 25 m (b) 2.5 cm (c) 25 cm (d) 2.5 m▾

Answer: (c) 25 cm

Q4The change in focal length of an eye lens is caused by the action of the (a) pupil (b) retina (c) ciliary muscles (d) iris▾

Answer: (c) ciliary muscles

Q5A person needs a lens of power −5.5 D for correcting distant vision, and +1.5 D for correcting near vision. Find the focal length required for each.▾

(i) Distant vision:

f = 1/P = 1/(−5.5) ≈ −0.182 m (≈ −18.2 cm)

(ii) Near vision:

f = 1/P = 1/(+1.5) ≈ +0.667 m (≈ +66.7 cm)
Q6The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?▾

A concave lens is needed so that an object at infinity forms a virtual image at the person's far point (80 cm = 0.8 m). Here u = −∞, v = −0.8 m.

1/f = 1/v − 1/u = 1/(−0.8) − 0 = −1.25
f = −0.8 m
Power P = 1/f = −1.25 D

A concave lens of power −1.25 D is required.

Q7Make a diagram showing how hypermetropia is corrected. The near point of a hypermetropic eye is 1 m. What power of lens is required to correct this (assume normal near point = 25 cm)?▾

Diagram: for the uncorrected hypermetropic eye, rays from a nearby object (at 25 cm) converge to a point behind the retina. Placing a convex lens in front of the eye converges the rays earlier, moving the focus point back onto the retina.

A convex lens is needed so that an object at the normal near point (25 cm) forms a virtual image at the person's actual near point (1 m). Here u = −0.25 m, v = −1 m.

1/f = 1/v − 1/u = 1/(−1) − 1/(−0.25) = −1 + 4 = 3
f = 1/3 m ≈ 0.33 m
Power P = 1/f = +3 D

A convex lens of power +3 D is required.

Q8Why is a normal eye not able to see clearly the objects placed closer than 25 cm?▾

The ciliary muscles of the eye can only increase the curvature (and reduce the focal length) of the eye lens up to a certain maximum limit. Beyond this limit, the lens cannot become curved enough to further decrease its focal length, so it cannot properly focus the image of objects closer than 25 cm onto the retina — the image would form behind the retina and appear blurred.

Q9What happens to the image distance in the eye when we increase the distance of an object from the eye?▾

The image distance stays essentially unchanged — the image is always formed on the retina, at a fixed distance from the eye lens, since the retina's position doesn't move. Instead, it is the focal length of the eye lens that changes (via accommodation, adjusted by the ciliary muscles) to keep the image sharply focused on the retina as the object distance changes.

Q10Why do stars twinkle?▾

Stars twinkle due to atmospheric refraction of starlight. As starlight enters the earth's atmosphere, it undergoes continuous refraction through layers of air with gradually and randomly changing refractive index, caused by varying physical conditions (temperature, etc.). Since stars are extremely distant, they act as point sources of light, so this continuously changing refraction causes the apparent position and brightness of the star to fluctuate — appearing alternately brighter and fainter, which is the twinkling effect.

Q11Explain why the planets do not twinkle.▾

Planets are much closer to Earth than stars, and are seen as extended sources of light rather than point sources — a planet can be thought of as a collection of many point-sized sources of light. Even though atmospheric refraction affects light from each of these individual points, the total variation in the amount of light reaching our eyes from all the points averages out to zero (the fluctuations cancel each other out), so the twinkling effect is not observed for planets.

Q12Why does the sky appear dark instead of blue to an astronaut?▾

The blue colour of the sky as seen from Earth's surface is due to the scattering of sunlight by fine particles/molecules in the atmosphere (blue light is scattered more than other colours). At very high altitudes, where astronauts are, there is little to no atmosphere present, so there is no scattering of sunlight. Without scattering, no light is redirected towards the observer's eyes from all directions, so the sky appears dark/black instead of blue.

Common Questions

Frequently Asked Questions

The power of accommodation is the eye's ability to adjust the focal length of its lens, using the ciliary muscles, so that it can focus clearly on both near and distant objects. A normal eye can see objects clearly between the near point (about 25 cm) and the far point (infinity).
Myopia (near-sightedness, where distant objects appear blurred) is corrected with a concave lens of suitable power, which diverges light rays so the image forms exactly on the retina instead of in front of it. Hypermetropia (far-sightedness, where nearby objects appear blurred) is corrected with a convex lens of suitable power, which converges light rays so the image forms on the retina instead of behind it.
Yes — numerical problems on correcting myopia and hypermetropia using the lens formula and power of a lens, along with conceptual questions on dispersion, twinkling of stars, and why the sky is blue, are frequently tested topics that appear almost every year in the CBSE board exam.
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