Free, step-by-step NCERT Solutions for both exercises of this chapter — mean deviation about the mean and the median for ungrouped, discrete, and continuous data, and variance and standard deviation with both the direct and shortcut step-deviation methods — plus the Miscellaneous Exercise on recovering missing observations and correcting wrongly recorded data. Solved the way CBSE awards marks, with the key formulas and the mistakes that cost students marks every year, right on this page.
Mean, median and mode describe where a data set is centred, but two very different-looking data sets can share the exact same mean. This chapter introduces measures of dispersion — numbers that describe how spread out or bunched-together the data actually is around that central value. Starting from the simple range, the chapter builds up to mean deviation and, finally, to variance and standard deviation — the most widely used measure of spread in statistics, and the one every later application (including probability distributions) is built on.
This Class 11 Maths NCERT Solutions Chapter 13 hub covers Statistics, the chapter that moves beyond measures of central tendency (mean, median, mode) into measures of dispersion — numbers that describe how scattered a data set is. The simplest of these is the range, the gap between the maximum and minimum values, but it ignores everything in between. Mean deviation improves on this by averaging the absolute distance of every single observation from a chosen central value, usually the mean or the median, calculated separately for ungrouped data, discrete frequency distributions, and continuous (grouped) frequency distributions.
Exercise 13.2 then introduces variance and standard deviation, obtained by squaring each deviation from the mean instead of taking its absolute value — a change that makes the resulting measure far more useful for further algebraic and statistical work. Both a direct calculation method and a faster shortcut (step-deviation) method are covered for grouped data. The Miscellaneous Exercise closes the chapter with reverse-engineering problems: recovering missing observations from a known mean and variance, working out how scaling every observation by a constant affects the mean and standard deviation, and correcting the mean and standard deviation when one or more observations were wrongly recorded.
Why a mean alone doesn't tell the whole story, and the simplest measure of spread. Exercise 13.1.
About the mean and the median, for ungrouped, discrete, and continuous data. Exercise 13.1.
Squaring the deviations instead of taking absolute values, plus the shortcut step-deviation method. Exercise 13.2.
Missing observations, scaling effects, and correcting wrongly recorded data. Misc. Exercise.
Everything you need before you start solving. This is a summary for quick recall — the Formula Cards below has the full printable version for all of Statistics.
Replace x̄ with the median M to get the mean deviation about the median instead.
N is the sum of all frequencies; for continuous data, xi is the mid-point of each class.
The simplest, fastest measure of spread — but it only uses two of the data points and ignores the rest.
Squaring the deviations avoids the positive/negative cancellation problem, without needing absolute values.
Same idea as ungrouped data, weighted by each value's frequency.
Using an assumed mean A and yi = (xi − A)/h keeps the arithmetic small even when the data values are large.
The key first step for almost every reverse-engineering problem in this chapter — find these two sums before doing anything else.
Multiplying every observation by a scales the mean by a and the variance by a².
Adding the same number to every observation shifts the mean but leaves the variance completely unchanged.
A quick way to decide, once you know what the question is actually asking for.
| What the question is asking | Use this | Why |
|---|---|---|
| Find mean deviation about the mean or the median | M.D. formula with absolute deviations | Compute the mean/median first, then average the absolute value of every deviation from it (§13.3–13.4). |
| Data is given as a continuous frequency distribution | Use class mid-points | Treat each class as concentrated at its mid-point, then proceed exactly as for discrete data (§13.4). |
| Find variance or standard deviation | Square the deviations from the mean | σ² = mean of the squared deviations; σ is its square root (§13.5). |
| The data values are large or awkward to work with directly | Shortcut (step-deviation) method | Pick an assumed mean A near the centre of the data and work with yi = (xi − A)/h instead (§13.5). |
| Some observations are missing but the mean/variance is known | Recover Σx and Σx² first | Use Σx = nx̄ and Σx² = n(σ² + x̄²), then solve the resulting equations for the missing values (Misc. Exercise). |
| Every observation is multiplied or added to by a constant | Apply the scaling/shifting rule | Multiplying scales the mean by the same factor and variance by its square; adding shifts the mean but not the variance (Misc. Exercise). |
| An observation was recorded wrongly and needs correcting | Adjust Σx and Σx², then recompute | Remove the wrong value (and add the correct one, if replacing) from both sums before finding the new mean and SD (Misc. Exercise). |
Drawn from where students actually lose marks across both exercises.
Mean Deviation — about the mean and the median, for ungrouped, discrete, and continuous data · 12 questions
Solve Exercise 13.1 →Variance and Standard Deviation — direct and shortcut step-deviation methods · 10 questions
Solve Exercise 13.2 →Missing observations, scaling effects, and correcting wrongly recorded data · 6 questions
Solve Miscellaneous →Every formula for Statistics — plus every other Class 11 Maths chapter — in one printable PDF.
Get Formula Cards →Quick answers from Class 11 Maths NCERT Solutions Chapter 13, Statistics.
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