Class 12 Maths NCERT Solutions Chapter 9 Ex 9.1 – Order and Degree of a Differential Equation | Boundless Maths
Ex 9.1 Class 12 Maths NCERT Solutions

Class 12 Maths NCERT Solutions Chapter 9 Ex 9.1 – Order and Degree of a Differential Equation

This Class 12 Maths NCERT Solutions Chapter 9 Ex 9.1 page covers all 12 questions, solved step-by-step — identifying the highest order derivative to find the order of a differential equation, and checking whether the equation is a polynomial in its derivatives to find the degree.

Questions 1–10 ask you to determine the order and degree of a range of differential equations, from straightforward polynomial forms to trickier ones where a derivative sits inside a trigonometric function — the exact situation where degree becomes not defined, a distinction CBSE tests almost every year. Questions 11 and 12 are multiple-choice versions of the same skill, reinforcing that order and degree, when defined, are always positive integers.

12Questions
Easy–MedDifficulty Mix
2026-27CBSE Syllabus

Class 12 Maths NCERT Solutions Chapter 9 Ex 9.1 — All 12 Questions

1

Determine order and degree (if defined) of \dfrac{d^4y}{dx^4}+\sin(y''')=0

Medium +
Solution

The highest order derivative present is \dfrac{d^4y}{dx^4}, so the order is 4.

For the degree to be defined, the equation must be a polynomial equation in all the derivatives that appear. Here y''' sits inside a sine function, \sin(y'''), so the equation is not a polynomial equation in its derivatives.

Answer: Order = 4, Degree = not defined
2

Determine order and degree (if defined) of y'+5y=0

Easy +
Solution

The highest order derivative present is y', so the order is 1.

The equation is a polynomial equation in y', and the highest power raised to y' is 1.

Answer: Order = 1, Degree = 1
3

Determine order and degree (if defined) of \left(\dfrac{ds}{dt}\right)^4+3s\dfrac{d^2s}{dt^2}=0

Medium +
Solution

The highest order derivative present is \dfrac{d^2s}{dt^2}, so the order is 2.

The equation is a polynomial equation in \dfrac{d^2s}{dt^2} and \dfrac{ds}{dt}, and the highest power raised to \dfrac{d^2s}{dt^2} is 1.

Answer: Order = 2, Degree = 1
4

Determine order and degree (if defined) of \left(\dfrac{d^2y}{dx^2}\right)^2+\cos\left(\dfrac{dy}{dx}\right)=0

Medium +
Solution

The highest order derivative present is \dfrac{d^2y}{dx^2}, so the order is 2.

Here \dfrac{dy}{dx} sits inside a cosine function, \cos\left(\dfrac{dy}{dx}\right), so the equation is not a polynomial equation in its derivatives — the degree cannot be defined even though the order can.

Answer: Order = 2, Degree = not defined
5

Determine order and degree (if defined) of \dfrac{d^2y}{dx^2}=\cos 3x+\sin 3x

Easy +
Solution

The highest order derivative present is \dfrac{d^2y}{dx^2}, so the order is 2.

The equation is a polynomial equation in \dfrac{d^2y}{dx^2} (the trigonometric terms involve only x, not a derivative), and the highest power raised to \dfrac{d^2y}{dx^2} is 1.

Answer: Order = 2, Degree = 1
6

Determine order and degree (if defined) of (y''')^2+(y'')^3+(y')^4+y^5=0

Medium +
Solution

The highest order derivative present is y''', so the order is 3.

The equation is a polynomial equation in y''', y'' and y', and the highest power raised to y''' is 2.

Answer: Order = 3, Degree = 2
7

Determine order and degree (if defined) of y'''+2y''+y'=0

Easy +
Solution

The highest order derivative present is y''', so the order is 3.

The equation is a polynomial equation in y''', y'' and y', and the highest power raised to y''' is 1.

Answer: Order = 3, Degree = 1
8

Determine order and degree (if defined) of y'+y=e^x

Easy +
Solution

The highest order derivative present is y', so the order is 1.

The equation is a polynomial equation in y' (the exponential term involves only x, not a derivative), and the highest power raised to y' is 1.

Answer: Order = 1, Degree = 1
9

Determine order and degree (if defined) of y''+(y')^2+2y=0

Easy +
Solution

The highest order derivative present is y'', so the order is 2.

The equation is a polynomial equation in y'' and y', and the highest power raised to y'' is 1.

Answer: Order = 2, Degree = 1
10

Determine order and degree (if defined) of y''+2y'+\sin y=0

Easy +
Solution

The highest order derivative present is y'', so the order is 2.

Here \sin y is a function of y itself, not of any derivative, so it doesn't affect whether the equation is a polynomial in its derivatives.

The equation is a polynomial equation in y'' and y', and the highest power raised to y'' is 1.

Answer: Order = 2, Degree = 1

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11

The degree of the differential equation \left(\dfrac{d^2y}{dx^2}\right)^3+\left(\dfrac{dy}{dx}\right)^2+\sin\left(\dfrac{dy}{dx}\right)+1=0 is

Hard +
Solution
(A) 3 (B) 2 (C) 1 (D) not defined

The highest order derivative present is \dfrac{d^2y}{dx^2}, giving order 2. But \dfrac{dy}{dx} appears inside a sine function, \sin\left(\dfrac{dy}{dx}\right).

Since the equation must be a polynomial equation in all the derivatives present — not just the highest order one — and it isn't a polynomial in \dfrac{dy}{dx}, the degree cannot be defined.

Answer: (D) not defined
12

The order of the differential equation 2x^2\dfrac{d^2y}{dx^2}-3\dfrac{dy}{dx}+y=0 is

Easy +
Solution
(A) 2 (B) 1 (C) 0 (D) not defined

The highest order derivative present in the equation is \dfrac{d^2y}{dx^2}, a second order derivative.

Answer: (A) 2
Common Questions

FAQs — Class 12 Maths NCERT Solutions Chapter 9 Ex 9.1

How many questions are there in Exercise 9.1?

Exercise 9.1 has 12 questions — the first 10 ask you to determine the order and degree (if defined) of a given differential equation, and the last 2 are multiple-choice questions on the same idea.

Why is the degree of a differential equation sometimes not defined?

Degree is only defined when the differential equation is a polynomial equation in its derivatives. If any derivative appears inside a non-polynomial function — such as sin, cos, or an exponential of a derivative — the equation is not a polynomial in that derivative, so the degree cannot be defined, even though the order can still be found.

Where can I find the official NCERT textbook for this exercise?

Exercise 9.1 is from Chapter 9, Differential Equations, in the NCERT Class 12 Mathematics textbook (Part II), published by the National Council of Educational Research and Training (NCERT) and prescribed by CBSE. You can download the official textbook PDF directly from ncert.nic.in, NCERT's official website — the solutions on this page follow the questions exactly as they appear there.

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